SOLUTION: A. Solve log4 (3x-7)<2
B.Solve log9 (3x-7)>= log9 (2x+9)
C. Evaluate (Log4 12^3) (log12 4^3)
Algebra.Com
Question 877918: A. Solve log4 (3x-7)<2
B.Solve log9 (3x-7)>= log9 (2x+9)
C. Evaluate (Log4 12^3) (log12 4^3)
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
A. Solve log4 (3x-7)<2
3x-7<16
3x<23
x<23/3
..
B.Solve log9 (3x-7)>= log9 (2x+9)
3x-7≥2x+9
x≥16
..
C. Evaluate (Log4 12^3) (log12 4^3)
convert to base 4
=3*3=9
RELATED QUESTIONS
Fill in the missing values to make the equations true.
The ? are the missing value... (answered by greenestamps)
1.) Solve each equation.
a.) log7(2x)^2+log7 (3)=2
b.) log4 (8)+log4 (x^2-8)=8
c.)... (answered by lwsshak3)
log4 3x=log4... (answered by Fombitz)
Solve for x:... (answered by Alan3354)
Which of the following is not correct
A. log4+log9=log36
B. log6+log6=log36
C.... (answered by solver91311,ewatrrr)
1.solve for x
log4 x^5=-1
2.solve for x in terms of k
log9 x + log9(x+9)=k
x=?... (answered by dabanfield)
Solve for x:
log4^8 + log4^6 =... (answered by Nate)
Log4 base2+log9... (answered by CPhill)
solve the equation log8(3x+7)=log8(7x-9)
log4(x)=3/2
loga(1/8)=-3... (answered by jsmallt9)