Question 876120: plz help me solve this
tan-1[tan(200)] where 200 is in radians.
I've tied to solve it:
x must be -pi/2 < x < pi/2
x= 200rad - pi = 20 rad (since tan is periodic)
so tan(inverse)(tan 20rad)= 20rad
because tan invrse and tan cancel each other
is my answer correct??
Found 2 solutions by Alan3354, Edwin McCravy:
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! tan (inverse)(tan 200 rad)
I've tied to solve it:
x must be -pi/2 < x < pi/2
x= 200rad - pi = 20 rad (since tan is periodic)
so tan(inverse)(tan 20rad)= 20rad
because tan invrse and tan cancel each other
is my answer correct??
============
tan (inverse)(tan 200 rad) = 200 rad
----
Subtract 2pi repeatedly until it's <= 2pi
= (200 MOD (2pi))*(2pi) =~ 5.221 radians
5.221 is not between -pi/2 and pi/2, so
5.221 - 2pi = -1.0619 radians
========================
email via the TY note if you don't know modulus aritmetic.
Answer by Edwin McCravy(20086)  (Show Source):
You can put this solution on YOUR website!
tan-1[tan(200)]
You may as well just punch it out entirely on a calculator,
since it doesn't involve a special angle. So you'll have to
have to use a calculator anyway. So there's no need to simplify it.
If you have a TI-83 of 84,
Press ON
Press CLEAR
If your calculator is already in radian mode, skip
these five steps, otherwise:
Press MODE
Press the down arrow key twice to scroll down to RADIAN
Press ENTER
Press 2ND
Press MODE
With calculator in radian mode,
Press 2ND
Press TAN, see tan-1(
Press TAN, see tan-1(tan(
Type 200)), see tan-1(tan(200))
Press ENTER, see -1.06192983
Answer: -1.06192983
Edwin
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