SOLUTION: plz help me solve this tan<sup>-1</sup>[tan(200)] where 200 is in radians. I've tied to solve it: x must be -pi/2 < x < pi/2 x= 200rad - pi = 20 rad (since tan is peri

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Question 876120: plz help me solve this
tan-1[tan(200)] where 200 is in radians.
I've tied to solve it:
x must be -pi/2 < x < pi/2
x= 200rad - pi = 20 rad (since tan is periodic)
so tan(inverse)(tan 20rad)= 20rad
because tan invrse and tan cancel each other
is my answer correct??
Found 2 solutions by Alan3354, Edwin McCravy:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
tan (inverse)(tan 200 rad)
I've tied to solve it:
x must be -pi/2 < x < pi/2
x= 200rad - pi = 20 rad (since tan is periodic)
so tan(inverse)(tan 20rad)= 20rad
because tan invrse and tan cancel each other
is my answer correct??
============
tan (inverse)(tan 200 rad) = 200 rad
----
Subtract 2pi repeatedly until it's <= 2pi
= (200 MOD (2pi))*(2pi) =~ 5.221 radians
5.221 is not between -pi/2 and pi/2, so
5.221 - 2pi = -1.0619 radians
========================
email via the TY note if you don't know modulus aritmetic.
Answer by Edwin McCravy(20086)   (Show Source): You can put this solution on YOUR website!
tan-1[tan(200)]    

You may as well just punch it out entirely on a calculator,
since it doesn't involve a special angle. So you'll have to 
have to use a calculator anyway. So there's no need to simplify it. 

If you have a TI-83 of 84,

Press ON
Press CLEAR

If your calculator is already in radian mode, skip 
these five steps, otherwise:

Press MODE
Press the down arrow key twice to scroll down to RADIAN
Press ENTER
Press 2ND
Press MODE

With calculator in radian mode,

Press 2ND
Press TAN, see  tan-1(
Press TAN, see  tan-1(tan(
Type 200)), see tan-1(tan(200))
Press ENTER, see -1.06192983

Answer: -1.06192983
  
Edwin
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