SOLUTION: What values for θ (0 ≤ θ ≤ 2pi) satisfy the equation?
2 sin θ cos θ + square root 3 cos θ = 0
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Question 874461: What values for θ (0 ≤ θ ≤ 2pi) satisfy the equation?
2 sin θ cos θ + square root 3 cos θ = 0
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
What values for θ (0 ≤ θ ≤ 2pi) satisfy the equation?
2 sin θ cos θ + square root 3 cos θ = 0
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Factor:
cos(t)[2sin(t) + sqrt(3)] = 0
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cos(t) = 0 or sin(t) = -sqrt(3)/2
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t = pi/2 or (3/2)pi or (4/3)pi or (5/3)pi
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Cheers,
Stan H.
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