SOLUTION: find the period of y=2 sin( 2/5 )θ
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Question 873817: find the period of y=2 sin( 2/5 )θ
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
find the period of y=2 sin( 2/5 )θ
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If y = asin(bx+c)
Period is (2pi)/b or 360/b
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Your Problem:
b = (2/5)
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Period = (2pi)/b = (2pi)/(2/5) = 5pi
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Cheers,
Stan H.
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