find the exact value of cos(a+B) if sin a= -4/5, and sin B= 5/13 cos(a) = ±√1-sinČ(a) == = = = cos(B) = ±√1-sinČ(B) = = = = = Case 1: a is in Q3 and B is in Q1 cos(a+B) = cos(a)cos(B) - sin(a)sin(B) = (-3/5)(12/13) - (-4/5)(5/13) = -16/65 Case 2: a is in Q3 and B is in Q2 cos(a+B) = cos(a)cos(B) - sin(a)sin(B) = (-3/5)(-12/13) - (-4/5)(5/13) = 56/65 Case 3: a is in Q4 and B is in Q1 cos(a+B) = cos(a)cos(B) - sin(a)sin(B) = (3/5)(12/13) - (-4/5)(5/13) = 56/65 Case 4: a is in Q4 and B is in Q2 cos(a+B) = cos(a)cos(B) - sin(a)sin(B) = (3/5)(-12/13) - (-4/5)(5/13) = -16/65 Two possible solutions: -16/65 and 56/65 Edwin