SOLUTION: cos(angle beta)= -15/17 and 180degrees<(angle beta)<270degrees find tan 2(angle beta) thats a question in my precalculus class *Note, i dont have all math symbols so i substit

Algebra.Com
Question 871548: cos(angle beta)= -15/17 and 180degrees<(angle beta)<270degrees
find tan 2(angle beta)
thats a question in my precalculus class
*Note, i dont have all math symbols so i substituded them with their real names

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi
cos θ = -15/17
3rd Quadrant Stated: sinθ = -8/17
tan θ = sinθ/cosθ = 8/15
(cosx, sinx) Unit Circle Summary Reference Below
Wish You the Best in your Studies.


RELATED QUESTIONS

Cos(beta)= √3/2 , find the missing angle (answered by Alan3354)
If cos beta= (-3/5) and is in the 2nd quadrant, find csc beta and tan... (answered by lwsshak3)
find {{{cos(beta)}}} and {{{tan(beta)}}} if {{{cos(2beta)=2/3}}}, {{{3pi/2 <... (answered by Alan3354)
without using a calculator where 0 (answered by ikleyn)
Find the exact value for sin(alpha-beta) if sin(alpha) = -5/13 and cos(beta) = -8/17 with (answered by ikleyn)
find exact value of a) sin(alpha+beta); b) cos(alpha+beta); c) tan(alpha-beta) given that (answered by stanbon)
Find beta if tan(beta) = 1.567 and beta is found in Quadrant... (answered by amarjeeth123)
If alpha and beta are acute angles such that csc alpha = 17/15 and cot beta = 5/12, find... (answered by ewatrrr)
please help me how would i solve: Use the fact that tan(beta)=4 to find:... (answered by stanbon,scott8148)