SOLUTION: Solve the equation for solutions over the interval [0, �360). Give solutions to the nearest tenth as appropriate. Cos^2(theta) - sin^2(theta) = 0

SOLUTION: Solve the equation for solutions over the interval [0, �360). Give solutions to the nearest tenth as appropriate. Cos^2(theta) - sin^2(theta) = 0

Algebra.Com

Question 870816: Solve the equation for solutions over the interval [0, �360). Give solutions to the nearest tenth as appropriate.
Cos^2(theta) - sin^2(theta) = 0
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Cos^2(theta) - sin^2(theta) = 0
cos(2theta)=0
2theta=90˚, 270˚
theta=45˚, 135˚
RELATED QUESTIONS
Solve the equation for solutions over the interval [0, 360). Give solutions to the... (answered by jim_thompson5910)

Solve the equation for solutions over the interval [0, 360). Give solutions to the... (answered by Fombitz)

Solve each equation for solutions over the interval [0 degrees, 360 degrees) . Give... (answered by lwsshak3)

Solve for the exact solutions over the interval (0�, 360�] Round to the nearest tenth... (answered by Fombitz)

solve equation for solutions over the interval (0 deg, 360 deg) cos^2 theta = sin^2... (answered by Alan3354)

Solve the equation for exact solutions over the interval (0 degrees, 360 degrees). Give... (answered by lwsshak3)

solve the equation for solutions over the interval [0 degrees, 360 degrees). 2 sin... (answered by lwsshak3)

solve for solutions over the interval (0 deg, 360 deg) 4 cos^2 theta + 4 cos theta = 1 (answered by stanbon)

Please help me with this problem. I need to solve the equation for solutions over the... (answered by Gogonati)