SOLUTION: Please explain hoe to solve the equation for exact solutions over the interval [0, 2pi).
Sin(x)+2=3
Algebra.Com
Question 870569: Please explain hoe to solve the equation for exact solutions over the interval [0, 2pi).
Sin(x)+2=3
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
RELATED QUESTIONS
Please explain how to solve the equation for exact solutions over the interval [0, 2pi).
(answered by Fombitz)
Please solve the equation for the interval [0, 2pi]:
{{{2sin^2(x)-sin(x)-1=0}}}... (answered by josgarithmetic)
Please help me with this problem. I need to solve the equation for solutions over the... (answered by Gogonati)
Solve the equation for exact solutions over the interval [0, 2π).
cos^2 x + 2 cos (answered by ikleyn)
step by step how to solve sin/2x=cos x/2 for exact solutions over the interval... (answered by jsmallt9)
Use a graphing utility to approximate the solutions of the equation in the interval[0,... (answered by Fombitz)
solve cos x/3 - sin x/3 = 0 over the interval [0,... (answered by ikleyn)
Solve the equation for exact solutions over the interval [0, 2π).
cos2x + 2 cos x (answered by ikleyn)
I need to solve this equation for the interval [0, 2pi) :
-sin^2(x) =... (answered by Boreal)