SOLUTION: URGENT HELP NEEDED! (Scale Drawing) (Q1) A destroyer and a cruiser leave a port at the same time. The destroyer sails at 38 knots on a bearing of 042 degrees and the cruiser sails

Algebra ->  Trigonometry-basics -> SOLUTION: URGENT HELP NEEDED! (Scale Drawing) (Q1) A destroyer and a cruiser leave a port at the same time. The destroyer sails at 38 knots on a bearing of 042 degrees and the cruiser sails      Log On


   

Question 870290: URGENT HELP NEEDED! (Scale Drawing)
(Q1) A destroyer and a cruiser leave a port at the same time. The destroyer sails at 38 knots on a bearing of 042 degrees and the cruiser sails at 25 knots on a bearing of 315 degrees. How far apart are the ships two hours later? [1 knot is a speed of 1 nautical mile per hour.]
(Q2)A control tower observes the flight of an unidentified flying object. At 09:23 the U.F.O. is 580 km away on a bearing of 043 degrees. At 09:25 the U.F.O. is 360 km away on a bearing of 016 degrees. What is the speed and the course of the U.F.O.? [Use a scale of 1 cm to 50 km]
PLEASE REPLY ASAP!
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
(Q1) A destroyer and a cruiser leave a port at the same time. The destroyer sails at 38 knots on a bearing of 042 degrees and the cruiser sails at 25 knots on a bearing of 315 degrees. How far apart are the ships two hours later?
The destroyer is 76 nm from the start.
The cruiser is 50 nm away.
Those are 2 sides of a triangle, and the included angle is 87 degrees.
Use the Cosine Law to find the distance between them.
c%5E2+=+a%5E2+%2B+b%5E2+-+2ab%2Acos%28C%29
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(Q2)A control tower observes the flight of an unidentified flying object. At 09:23 the U.F.O. is 580 km away on a bearing of 043 degrees. At 09:25 the U.F.O. is 360 km away on a bearing of 016 degrees. What is the speed and the course of the U.F.O.?
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Similar to Q1
You have 2 sides and the included angle.