SOLUTION: <pre><Please help me solve equation {{{ cos(2x)}}} - {{{sIn^2x/2 }}} + {{{3/4}}} = {{{0}}} please give values between 0 to 360 degrees and give values to the nearest minut

Please help me solve equation 

 -  +  = 

please give values between 0 to 360 degrees and give 
values to the nearest minute.

Multiply the equation through by LCD = 4

 -  +  =  

Simplifying:

 -  +  = 

Use the identity cos 2q = 1 - 2sin²q

to substitute 1 - 2sin²x for cos(2x) in the first term:

 -  +  = 

Remove the parentheses by distributing:

 -  +  = 

Combine like terms:

 = 

 = 

 = 

 = 

Take the square roots of both sides:

 = ±

 = ±

Find the inverse sine of .836600265 in the
first quadrant:

 = 56.78908924°

To change the decimal part of that to minutes, 
multiply the decimal part .78908924 by 60, getting
47.34535435' then round to the nearest minute, so
the value of x is the first quadrant is 56°47'.

But since the  can be positive or 
negative, we will get all the angles in all the
quadrants which have 56²47 as their reference
angles.

The second quadrant answer is found by
subtracting 56°47' from 180° or

180° - 56°47' = 179°60' - 56°47' = 123°13'

The third quadrant answer is found by
adding 56°47' to 180° or

180° + 56°47' = 236°47'

The fourth quadrant answer is found by
subtracting 56°47' from 360°

360° - 56°47' = 359°60' - 56°47' = 303°13'

So all the answers for x between 0° and 360° are

x = 56°47', 123°13', 236°47', and 303°13

Edwin