SOLUTION: I have to solve 3cosx = cosx -1 in the interval 0≤x<2π
Algebra.Com
Question 869271: I have to solve 3cosx = cosx -1 in the interval 0≤x<2π
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
solve 3cosx = cosx -1 in the interval 0≤x<2π
3cosx = cosx -1
2cosx = -1
cos x=-1/2
x=5π/6, 7π/6 (In quadrants II and III in which cos<0)
RELATED QUESTIONS
Solve each equation for x in the interval 0≤x ≤2 π:
1/1+tan²x=-cosx
(answered by stanbon)
Solve this equation graphically on the interval [0, 2π]. Sketch the graph and list... (answered by Alan3354)
Solve for x in the equation (1 +sinx/cosx)+(cosx/1+sinx)=4 for 0≤ x ≤ 2π (answered by HyperBrain)
could you help me find all the solutions in the interval [0, 2pi)... (answered by lwsshak3)
A) express cos3x in terms of cosx. I have already gotten the answer for this to be... (answered by Alan3354)
Question:
Solve over the interval [0 degrees, 360 degrees):
3cos^2x-4cosx-2=0
I... (answered by jsmallt9)
solve for x on the interval [0,2pi)
3cosx-1=2
first i isolated cosx and got cosx=1
i... (answered by ikleyn)
Solve the cos x-1 =0 on the interval 0≤x≤pi/2
x+ π/3
x=0
x=π/6... (answered by richard1234)
Solve the equation algebraically for "x" where 0≤x<2π.
sinx + cosx = 1... (answered by Fombitz)