SOLUTION: Please help me solve this problem Solve the equation on the interval 0 < x

SOLUTION: Please help me solve this problem Solve the equation on the interval 0 < x < 2(pi) Sin^2(x) + sin (x) = 0

Question 865399: Please help me solve this problem
Solve the equation on the interval 0 < x < 2(pi)
Sin^2(x) + sin (x) = 0
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
sin^2(x) + sin(x) = 0

sin(x)( sin(x) + 1 ) = 0

sin(x) = 0 or sin(x) + 1 = 0

sin(x) = 0 or sin(x) = -1

x = arcsin(0) or x = arcsin(-1)

x = 0,pi or x = 3pi/2

The three solutions are x = 0, x = pi, x = 3pi/2
RELATED QUESTIONS
Solve 2 sin^2 x + cos x -2=0 on the interval -pi< x <... (answered by lwsshak3)

Solve on the interval from 0 to pi:2cos^2 x-3 sin... (answered by lwsshak3)

Please help me solve this equation for all the solutions in the interval [0, 2 pi)... (answered by stanbon)

Please help me with this problem. I need to solve the equation for solutions over the... (answered by Gogonati)

Hello,Can you please help me solve this problem: 1.Solve the following equation for x... (answered by Edwin McCravy)

Solve the equation on the interval [0, 2pi). tan^2 x sin x = tan^2 x B.pi/2 , pi (answered by ikleyn)

Solve the equation on the interval [0,2pi) 2 cos^2 x + sin x -2 =... (answered by stanbon)

Please solve the equation sin*(2*x+(pi/3)) = 1/2 for x is [0,pi] Show... (answered by josmiceli)

Solve the equation on the interval [0,2pi), sin(2(x)+pi/6) =... (answered by lwsshak3)