SOLUTION: Find the polar coordinates of the point whose rectangular coordinates are (4sqrt 3, -4) Find the rectangular coordinates of the point whose polar coordinates are (-4, π/6).

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Question 865281: Find the polar coordinates of the point whose rectangular coordinates are (4sqrt 3, -4)
Find the rectangular coordinates of the point whose polar coordinates are (-4, π/6).
Find a rectangular form of the equation r = 5 cos θ

Found 2 solutions by Edwin McCravy, stanbon:
Answer by Edwin McCravy(20056)   (Show Source): You can put this solution on YOUR website!
Find the polar coordinates of the point whose rectangular coordinates are
(, -4)
We will indicate the rectangular coordinates of point P in 
black as  and the polar coordinates of point P
in red as 

Plot P using its rectangular coordinates  = (:



The x-coordinate of point P is  and the y-coordinate
of point P is -4.

Draw a right triangle with this point P and the origin as
vertices and the right angle on the x-axis.  The legs of this right
triangle x and y are the RECTANGULAR coordinates of point P. The 
hypotenuse r of this right triangle is the first POLAR coordinate 
of P.  The angle  indicated by the counter-clockwise red 
arc is the second POLAR coordinate of the point  



We only need to calculate  and 










Therefore  in the 4th quadrant is , and

 = 



Find the rectangular coordinates of the point whose polar coordinates are
.
Let's draw the point  using its polar coordinates.

First we draw the angle  with a dotted line through
the origin:



Next we locate the value of r on the x-axis, then we swing an
arc from that point on the x-axis around to the dotted line,
like the green arc below swinging from -4 on the x-axis to
the dotted line, and mar that point .



Then we erase the green arc and draw a right triangle with 
this point P and the origin as vertices and the right angle 
on the x-axis, and indicate the RECTANGULAR coordinates x,
y, of the point P.  Since we swung the point from the point
x=-4, the hypotenuse .

  

Now we calculate x and y.













So  = 



Find a rectangular form of the equation
Always substitute trig functions first, 

, , 

and always wait until last to replace  by 








You can then put it in standard form of a circle,



getting:



whose graph is a circle with center (h,k) = (,0) 

and radius : 



Edwin

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
Find the polar coordinates of the point whose
rectangular coordinates are (4sqrt 3, -4)
Note:: the point is in QIV so the angle is in QIV
-----------------
r = sqrt[(4sqrt(3))^2 + 4^2] = sqrt[64] = 8
angle = t = arctan(-4/4sqrt(3)) = arctan(-1/sqrt(3)) = (11/6)pi
Ans: (8,(11/6)pi)
====================================
Find the rectangular coordinates of the point
whose polar coordinates are (-4, π/6).
x = -4(cos(pi/6)) = -4(sqrt(3)/2) = -2sqrt(3)
y = -4(sin(pi/6)) = -4(1/2) = -2
=====================================
Find a rectangular form of the equation
r = 5 cos θ
----
r = sqrt(x^2+y^2)
theta = arctan(y/x)
----
Therefore cos(theta) = x/sqrt(x^2+y^2)
----------------------
Substituting you get:
=================
sqrt(x^2+y^2) = 5*x/sqrt(x^2+y^2)
--------
x^2 + y"^2 = 5x
----
Cheers,
Stan H.
=================




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