SOLUTION: Find the exact value of:
sin(2cos^-1(24/25))
and
tan(cos^-1(1/5))
Algebra.Com
Question 863561: Find the exact value of:
sin(2cos^-1(24/25))
and
tan(cos^-1(1/5))
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find the exact value of:
sin(2cos^-1(24/25))
Note: sin(2t) = 2sin(t)*cos(t)
------
Since cos = (24/25), sin = sqrt(25^2-24^2)/25 = 7/25
Therefore: sin(2cos^-1(24/25)) = 2(7/25)(24/25) = 0.5376
------------------------------------------------------------
and
--------------------------
tan(cos^-1(1/5))
---
Let t = cos-1(1/5)
Since cos(t) = 1/5, x = 1 and r = 5
Then y = sqrt(5^2-1^2) = 2sqrt(6)
-----
Ans: tan(t) = y/x = (2sqrt(6))/1 = 2sqrt(6)
=============================================
Cheers,
Stan H.
===================
RELATED QUESTIONS
Find the exact value of
Sin(Tan-1 7/24)
Cos-1(Cos 4Pi/3)
(answered by jsmallt9)
given sin(theta)= -1/5 and tan(theta)< 0, find the exact value of... (answered by richard1234)
Find the exact value of the expression
sin((tan^-1 3/4) +(cos^-1... (answered by lwsshak3)
find the exact value of... (answered by lwsshak3)
Find the exact value of
sin(tan^-1... (answered by lwsshak3)
Find the exact value of the expression.
sin(cos^-1 2/3 - tan^-1... (answered by KMST)
find the exact value of cos(sin inverse 1/3 - tan inverse... (answered by lwsshak3)
Find exact value of... (answered by Alan3354)
find exact value of... (answered by kev82)