SOLUTION: Please show the steps on how to solve: Find the vertex, focus, and directrix of the parabola given by the equation x^2 - 8x-16y+16 =0

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Question 860387: Please show the steps on how to solve:
Find the vertex, focus, and directrix of the parabola given by the equation x^2 - 8x-16y+16 =0

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
x^2 - 8x-16y+16 =0
x^2 - 8x = 16y-16
(x-4)^2 = 16y - 16 + 16
(x-4)^2 = 16y
y = (1/16)(x-4)^2 V(4,0) x = 4 line of symmetry
, p = 4, focus(4,4), y = -4 directrix


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