SOLUTION: 1+cscA=cscA(1+sinA) ~ How to prove that LS=RS

Question 860074: 1+cscA=cscA(1+sinA) ~ How to prove that LS=RS
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
I'm only going to be altering the right side.

1+cscA=cscA(1+sinA)

1+cscA=cscA(1)+cscA(sinA) ... distribution

1+cscA=cscA(1)+1/sinA(sinA) ... Substitution (note: csc(A) = 1/sin(A))

1+cscA=cscA+sinA/sinA ... multiplication

1+cscA=cscA+1 ... division

1+cscA=1+cscA ... use the commutative property of addition

So the identity is confirmed.
RELATED QUESTIONS
Prove that : 1. (cscA-1)/(cscA+1) = (1-sinA)/(1+sinA) 2. (secA/cscA)+(sinA/cosA) =... (answered by Edwin McCravy)

prove sinA tanA = (cotA cscA)/(cotA... (answered by Edwin McCravy)

1+cscA=cscA(1+sinA) I just need the full steps of how to solve them and I will... (answered by ewatrrr)

Prove the following: a) CosA = CotA SecA b) SinA = CscA (1+CosA) (answered by Alan3354)

Prove the following: a) CosA/SecA = CotA b) SinA/1-CosA = CscA (1+CosA) (answered by Alan3354)

(cscA+1)(cscA-1)=cot^2A (answered by MathLover1)

1+cosa/1+sina times... (answered by MathLover1,Alan3354)

Simplify:... (answered by Alan3354)

Simplify:... (answered by Leaf W.)