SOLUTION: Find the vertex, focus and directrix of the parabola given by the equaiton (y + 2)^2 + -4(x-1)

Question 857859: Find the vertex, focus and directrix of the parabola given by the equaiton (y + 2)^2 + -4(x-1)
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
You are missing something. There should be an equal sign somewhere.
Maybe you meant to type
(y + 2)^2 = -4(x-1) and got a + sign instead of the intended = sign.

<-->
is the equation of a parabola with a horizontal axis of symmetry,
<--> ,
and the vertex at (1,-2).
The focal distance is ,
and the focus and the rest of the parabola are to the left.
So the focus is at (0,-2),
unit to the left of (1,-2),
and the directrix is the line ,
unit to the left of (1,-2).

RELATED QUESTIONS
Please explain the necessary steps to solve the following question: Find the vertex,... (answered by ewatrrr)

Find the equaiton in standard form of the parabola with the directrix x = 3 and vertex... (answered by stanbon)

Identify the vertex, focus, and directrix of the parabola.... (answered by stanbon)

Find the vertex, focus, and directrix of the parabola given by the equation... (answered by RAY100)

Find the vertex, focus, and directrix of the parabola.... (answered by lwsshak3,TimothyLamb)

Find the vertex, focus, and directrix of the parabola given by the equation (x-1)^2 =... (answered by lwsshak3)

Find the vertex, focus, directrix, and focal width of the parabola. -1/40 x^2=... (answered by josgarithmetic)

parabola,x^2 +6x -y +11 =0 find the vertex,focus and directrix of the... (answered by lwsshak3)

Find the vertex, focus, and directrix of the parabola.... (answered by lwsshak3)