SOLUTION: Solve the following equation in the interval 0 < theta < 2pi. Give your final answers in radians correct to 3 sf 5*sin^2(theta)-3 =2sin(theta)+4cos^2(theta) thanks in adv

Question 857628: Solve the following equation in the interval 0 < theta < 2pi. Give your final answers in radians correct to 3 sf

5*sin^2(theta)-3 =2sin(theta)+4cos^2(theta)
thanks in advance
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Solve the following equation in the interval 0 < theta < 2pi. Give your final answers in radians correct to 3 sf
5*sin^2(theta)-3 =2sin(theta)+4cos^2(theta)

(9sinx+7)(sinx-1)=0
..
9sinx+7=0
sinx=-7/9
x≈0.891
or
sinx-1=0
sinx=1
x=π/2

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