Hi,
acute angle θ,
θ radians sin θ cos θ tan θ
0° 0 0 1 0
30° π/6 1/2 √3/2 √3/3
45° π/4 √2/2 √2/2 1
60° π/3 √3/2 1/2 √3
90° π/2 1 0 ─
cot(θ)=1
tan(θ)=1
sin(θ)= √2/2
csc(θ)= 2/√2
cos(θ)=√2/2
sec(θ)=2/√2
Following (cosx, sinx) Unit Circle Summary for Your reference, as well
You were to sketch a triangle, not a circle. cot(θ)=1 The cotangent is the adjacent over the opposite. Write the 1 asThen when we draw the right triangle, we will make the adjacent side to equal to the numerator of , which is 1 and the opposite side of equal to the denominator of which is 1 as well, so the right triangle is: Now we calculate the hypotenuse by the Pythagorean theorem: Now the adjacent side = 1, the opposite side = 1, and the hypotenuse = And you were already given: Edwin