SOLUTION: Given that cos C = -5/13 with C in quadrand II, find tan 2c I tried using tan(2x) = 2tan(x) / (1 - tan(x)2 but i have no idea?

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Question 850183: Given that cos C = -5/13 with C in quadrand II, find tan 2c
I tried using tan(2x) = 2tan(x) / (1 - tan(x)2
but i have no idea?
Answer by fcabanski(1391)   (Show Source): You can put this solution on YOUR website!
cos is adjacent/hypotenuse. So the adjacent side to the angle (one of the legs) is 5. Since this is quadrant II, it's -5. The hypotenuse is 13. You can find the other leg (opposite side) using the Pythagorean theorem where a and b are legs and h is the hypotenuse. This can be rearranged as



tan2c = -24/5 / (1-144/25) = -24/5 / (-119/25) = -24/5 * -25/119 = 120/119 = approximately 1.008

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