SOLUTION: sine theta = 1/4, 0 degrees < theta < pi/2; cosine theta
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Question 846321: sine theta = 1/4, 0 degrees < theta < pi/2; cosine theta
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
sine theta = 1/4, 0 degrees < theta < pi/2; cosine theta
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By definition sin = y/r, so y = 1 and r = 4
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Therefore x = sqrt[4^2-1^2] = sqrt(15)
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cos(t) = x/r = sqrt(15)/4
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Cheers,
Stan H.
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