SOLUTION: sinx-tanx=0
Algebra.Com
Question 845247: sinx-tanx=0
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
sin(x) - tan(x) = 0
sin(x) - sin(x)/cos(x) = 0
sin(x)*cos(x)/cos(x) - sin(x)/cos(x) = 0
(sin(x)*cos(x) - sin(x))/cos(x) = 0
sin(x)*cos(x) - sin(x) = 0*cos(x)
sin(x)*cos(x) - sin(x) = 0
sin(x)( cos(x) - 1 ) = 0
sin(x) = 0 or cos(x) - 1 = 0
sin(x) = 0 or cos(x) = 1
x = arcsin(0) or x = arccos(1)
x = pi*n or x = 2pi*n
x = pi*n
So the solution set is the set of all x such that x = pi*n where n is an integer. This is of course if we're in radian mode.
RELATED QUESTIONS
tanx... (answered by Alan3354)
tanx... (answered by Alan3354)
-sinx/-tanx*tanx*cosx (answered by ikleyn)
(Sinx+tanx)(sinx÷1+cosx)=sinx×tanx prove the identity (answered by josgarithmetic,MathTherapy)
cosx+sinx-tanx/cscx (answered by Edwin McCravy)
What is... (answered by stanbon)
cosx+tanx(sinx)=secx (answered by vleith)
secx/cotx+tanx=sinx (answered by Alan3354)
cosx + sinx tanx... (answered by srinivas.g)