SOLUTION: Please help me solve this equation: One of the equal sides of an isosceles triangles is 2cm and one of the base angle is 30 degrees. Find the base, altitude and vertical angle.

Algebra.Com
Question 835321: Please help me solve this equation: One of the equal sides of an isosceles triangles is 2cm and one of the base angle is 30 degrees. Find the base, altitude and vertical angle.
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
Please help me solve this equation: One of the equal sides of an isosceles triangles is 2cm and one of the base angle is 30 degrees. Find the base, altitude and vertical angle.
--------
Draw the figure:
You have an isosceles triangle with each base angle = 30 degrees.
The vertical angle is 180-2*30 = 120 degrees
------------------
Draw an altitude from the vertex to the base
That altitude is opposite a 30 degree angle.
sin(30) = altitude/hypotenuse
----
1/2 = altitude/2
---
altitude = 1 cm
-------------------------
Cheers,
Stan H.
=========================

RELATED QUESTIONS

2 isosceles triangles have legs that are 26 and areas that are equal. If the base of one... (answered by ewatrrr)
An isosceles trapezoid is inscribed in a circle, the upper base is 12cm, the other base... (answered by rothauserc)
Please help me with this question! what is the measure of the vertex angle of an... (answered by fractalier)
The length of the base of an isosceles triangle is 4 inches less than the length of one... (answered by checkley75)
please help me solve this problem: the vertex angle of an isosceles triangle is 57... (answered by Edwin McCravy)
Please help me solve this problem: the vertex 
angle of an isosceles triangle is... (answered by stanbon,Edwin McCravy)
The perimeter of an isosceles triangle is 40 and the base is 10. Find the length of one... (answered by rothauserc)
please help me solve this: each base of an isosceles triangle is 15 more than the vertex... (answered by solver91311)
Please help me with this question.... Find the measure of the vertex angle of an... (answered by cleomenius)