SOLUTION: if the Area of a rectangle is 105 sq. in., and the Perimeter is 44 in., what would be the measurement of its' length and width? This is what I've done so far; A=1w (105 sq.

Question 834921: if the Area of a rectangle is 105 sq. in., and the Perimeter is 44 in., what would be the measurement of its' length and width?
This is what I've done so far; A=1w (105 sq. in)
P=2(1+w) = 44
Answer by josgarithmetic(39630) (Show Source): You can put this solution on YOUR website!
That is a good start. CONTINUE!

Let's use L for length instead of the lower case "l", because it looks like a variable and not a digit.

You know area A and you know perimeter P.
You want to know length L and width w.

Equations for the system are as you saw, and .

Solve for one unknown from one equation and substitute the formula into the other equation! That is what is meant by, "CONTINUE!". I will keep this generalized, really not caring about the actual values of P and A.

--------- If the values for A and P make this factorable, then you can solve that way. Otherwise, use the general solution for a quadratic equation:

And find L from knowing value of w.
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