SOLUTION: We are having a hard time understanding why the Arcsin (-1) is -90 degrees. We know that the reference triangle is a 45,45,90 degree triangle. Sin is opp/adj so this makes no sense

Question 826871: We are having a hard time understanding why the Arcsin (-1) is -90 degrees. We know that the reference triangle is a 45,45,90 degree triangle. Sin is opp/adj so this makes no sense to me. Please explain this for me.
Thanks ahead of time for helping me.
Caleb
Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
The graph of the sine function depicts a periodic function which is not 1-1 unless we restrict the domain where the function is 1-1, the restriction is on the interval [-pi/2, pi/2] where pi is 180 degrees. Note that the x-axis is in radians (i.e. there are 2pi radians in a circle, 90 degrees is pi/2 radians)

We see that the graph of y = arcsin x is 1-1 over [-1, 1], y axis is in radians

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