SOLUTION: Given cos 6 theta = 4/5, P(6 theta) belongs to Q1, tan (6 theta) is equal to
a) 3/4
b) 4/3
c) - 3/4
d) - 4/3
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Question 824914: Given cos 6 theta = 4/5, P(6 theta) belongs to Q1, tan (6 theta) is equal to
a) 3/4
b) 4/3
c) - 3/4
d) - 4/3
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
All angles in quadrant 1 are acute angles, and all acute angles are in quadrant 1.
In the right triangle below, the acute angle has
= (adjacent side)/(hypotenuse) =
According to the Pythagorean theorem,
So = (opposite side)(adjacent side) =
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