Hi,

Find the real zeroes of 

g(x)=x^3-11x^2+26x-16    |Note:  x = 1 is a root  (1-11 +26- 16 )= 0

Using synthetic division: dividing by (x-1)

1	1	-11	26	-16

		1	-10	16

	1	-10	16	0

g(x) =  (x-1)(x^2 - 10x + 16)

g(x) =  (x-1)(x - 8)(x - 2)

 roots are:  1, 2 , 8 

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