SOLUTION: sinx + cosx =sqrt2 (solve on the interval [0,2pi]

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Question 821210: sinx + cosx =sqrt2 (solve on the interval [0,2pi]
Answer by lwsshak3(11628) About Me  (Show Source):
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sinx + cosx =sqrt2 (solve on the interval [0,2pi]
try x=π/4
sin(π/4)+cos(π/4)=√2/2+√2/2=2√2/2=√2
so, x=π/4