SOLUTION: solve 12sin^2(x)+2sin(x)-2=0 for all solutions where x is in radians between 0 and 2pi

SOLUTION: solve 12sin^2(x)+2sin(x)-2=0 for all solutions where x is in radians between 0 and 2pi

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Question 816104: solve 12sin^2(x)+2sin(x)-2=0 for all solutions where x is in radians between 0 and 2pi
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
solve 12sin^2(x)+2sin(x)-2=0 for all solutions where x is in radians between 0 and 2pi
***

divide by 2

solve for sin(x)
(3sin(x)-1)(2sin(x)+1)=0
..
3sin(x)-1=0
sin(x)=1/3
x≈0.34, 2.80
or
2sin(x)+1=0
sin(x)=-1/2
x=7π/6,11π/6

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