SOLUTION: Simplify cscx- cosxcotx I rewrote the problem using reciprocals and quotients to get {{{1/sinx- 1/secx*cosx/sinx}}}. Then I multiplied the reciprocals of cosx and cotx to get {{{1

Algebra.Com
Question 816076: Simplify cscx- cosxcotx
I rewrote the problem using reciprocals and quotients to get . Then I multiplied the reciprocals of cosx and cotx to get I'm not sure what to do after that.

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
Simplify cscx- cosxcotx
I rewrote the problem using reciprocals and quotients to get . Then I multiplied the reciprocals of cosx and cotx to get I'm not sure what to do after that.
===============
cscx- cosxcotx
---
= 1/sin - cos^2/sin
= (1 - cos^2)/sin
= sin^2/sin
= sin(x)

RELATED QUESTIONS

Prove using reciprocal and pythagorean identities: (cscx-cotx)/(secx-1)= cotx I have... (answered by jsmallt9)
Simplify Sinx cscx + cosx... (answered by srinivas.g)
I believe I did the problem correctly, but would like some assurance. Proving a trig... (answered by jim_thompson5910)
Simplify the expression: cscx + secx / sinx + cosx I know that the first step is to (answered by MathLover1)
please help me solve this problem using exact values {{{sinx=2/5}}} and {{{cosx<0}}} I... (answered by stanbon)
Please show me how to prove: (cscx-1)(1+cscx)=(cscx cosx)/(secx... (answered by addingup,MathTherapy)
Verify the identity sinx/1-cosx = cscx +cotx. I switched the cscx with 1/sinx and cotx (answered by MathLover1)
I'm am trying to do a proof where (sinx - 2 + 1/sinx)/(sinx - 1/sinx) = (sinx - 1)/(sinx... (answered by hamsanash1981@gmail.com)
How do you prove that this is an identity? sinX/cosX + cosX/sinX = secX cscX I've... (answered by jim_thompson5910)