SOLUTION: solve sin^2(t)=-5cos(t) for all solutions where t is in radians between 0 and 2pi. Give your answers accurate to 2 decimal places, as a list separated by commas

SOLUTION: solve sin^2(t)=-5cos(t) for all solutions where t is in radians between 0 and 2pi. Give your answers accurate to 2 decimal places, as a list separated by commas

Algebra.Com

Question 815619: solve sin^2(t)=-5cos(t) for all solutions where t is in radians between 0 and 2pi. Give your answers accurate to 2 decimal places, as a list separated by commas
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
solve sin^2(t)=-5cos(t) for all solutions where t is in radians between 0 and 2pi.
------------
Hint: sin^2 = 1 - cos^2

RELATED QUESTIONS
solve 12sin^2(w)+13cos(w)-15=0 for all solutions where w is in radians between 0 and 2pi. (answered by jsmallt9)

Solve the equations below exactly. Give your answers in radians, and find all possible... (answered by ikleyn)

Solve the equations below exactly. Give your answers in radians, and find all possible... (answered by Fombitz)

solve 12sin^2(x)+2sin(x)-2=0 for all solutions where x is in radians between 0 and... (answered by lwsshak3)

solve 3sin^2(w)-17sin(w)+10=0 for all solutions where w is in radians between 0 and... (answered by jsmallt9)

Solve for t in the interval [0, 2pi) cos^2(t)-sin^2(t)=0 (answered by stanbon)

Find all the solutions t in the interval (0, 2pi) to the equation sin (2t) = sqare root (answered by lwsshak3)

Find all solutions t in the interval [0 , 2pi] to the equation sin(2t) = square root of 2 (answered by lwsshak3)

find all solutions t in the interval (0, 2pi) to the equation sin(2t)=square root of 2... (answered by stanbon)