SOLUTION: Suppose a triangle has three sides which measure 10, 13, and 17. Find the measure of the smallest angle, to the nearest degree.
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Question 812660: Suppose a triangle has three sides which measure 10, 13, and 17. Find the measure of the smallest angle, to the nearest degree.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Suppose a triangle has three sides which measure 10, 13, and 17. Find the measure of the smallest angle, to the nearest degree.
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The smallest angle is opposite the shortest side.
Let that side be "a".
Use the Law of Cosines to get:
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cos(A) = (13^2+17^2-10^2)/(2*13*17) = 0.81
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angle A = cos^-1(0.81) = 35.8 degrees
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Cheers,
Stan H.
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