SOLUTION: find all solutions t in the interval (0, 2pi) to the equation sin(2t)=square root of 2 cos (t)

Question 810408: find all solutions t in the interval (0, 2pi) to the equation sin(2t)=square root of 2 cos (t)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
find all solutions t in the interval (0, 2pi) to the equation
sin(2t)=square root of 2 cos (t)
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2*sin(t)(cos(t)) = sqrt(2)*cos(t)
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2*sin(t) = sqrt(2)
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sin(t) = sqrt(2)/2
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t = pi/4 or t = (3/4)pi
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Cheers,
Stan H.
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