Question 810319: Solve the equation cos2theta=-√3/2
A) On the Interval [0,2pi)
B) On (-infinity,Infinity)
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Solve the equation cos2theta=-√3/2
A) On the Interval [0,2pi)
B) On (-infinity,Infinity)
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cos(2x)=1-2sin^2x=-√3/2
2sin^2x=1+√3/2=(2+√3)/2
sin^2x=(2+√3)/4
sinx=±√(2+√3)/4=±√(2+√3)/2=±0.9659
A)[0,2pi)
x=1.3089,1.8327,4.4504,4.9743
..
B)(-∞,∞)
1.3089±2πk,1.8327±2πk,4.4504±2πk,4.9743±2πk, k=any integer
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