SOLUTION: Solve each equation for solutions over the interval [0,2pi).
2tanx - 1 = 0
I did x = tan^-1(1/2)but I did not get the right answer.
Correct answer: {0.463647609,3.605240
Algebra.Com
Question 809378: Solve each equation for solutions over the interval [0,2pi).
2tanx - 1 = 0
I did x = tan^-1(1/2)but I did not get the right answer.
Correct answer: {0.463647609,3.605240263}
Could you please explain how to solve this and these types of problems? I am having a really hard time understanding this.
Thanks!
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
The calculator would tell you that in radians,
or in degrees.
That is because the inverse function of tangent is defined as the angle that has that tangent and is between and in radians,
or between and in degrees.
However, the function tangent has a period of radians (or in degrees.
That means, in other words, that .
That gives you the other solution,
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