SOLUTION: Find the values of theta in [0 degrees, 360degrees) to the nearest tenth that satisfies the following equation 6 sin^2theta +sin theta=2

Question 807942: Find the values of theta in [0 degrees, 360degrees) to the nearest tenth that satisfies the following equation
6 sin^2theta +sin theta=2
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Find the values of theta in [0 degrees, 360degrees) to the nearest tenth that satisfies the following equation
6 sin^2theta +sin theta=2
***
use x for theta

(3sin(x)+2)(2sin(x)-1)=0
..
3sinx+2=0
sinx=-2/3
x=221.81˚, 318.19˚ (In quadrants III and IV where sin<0)
or
2sin(x)-1=0
sinx=1/2
x=30˚, 150˚ (In quadrants I and II where sin>0)
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