SOLUTION: Hello, I do not know how to find this answer....please help! Solve the equation for x in the interval [0,2pi] 18sinx=8(cos^2)x-15 Thank you!

SOLUTION: Hello, I do not know how to find this answer....please help! Solve the equation for x in the interval [0,2pi] 18sinx=8(cos^2)x-15 Thank you!

Algebra.Com

Question 806093: Hello,
I do not know how to find this answer....please help!
Solve the equation for x in the interval [0,2pi]
18sinx=8(cos^2)x-15
Thank you!
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Solve the equation for x in the interval [0,2pi]
18sinx=8(cos^2)x-15
--------------
Sub 1 - sin^2 for cos^2, then it's a quadratic.

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