SOLUTION: Find all values of t in the interval [0, 2π] satisfying the given equation: 6 sin 2t + 3 tan 2t = 0. And 6 is under a square root! How to get the answer? Thank you!

Question 805610: Find all values of t in the interval [0, 2π] satisfying the given equation: 6 sin 2t + 3 tan 2t = 0. And 6 is under a square root! How to get the answer? Thank you!
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Find all values of t in the interval [0, 2π] satisfying the given equation:
6 sin 2t + 3 tan 2t = 0. And 6 is under a square root
------------

Use x for 2t

sin(x) = 0
x = 2t = 0, pi, 2pi
t = 0, pi/2, pi
------------------

|cos(x)| > 1, no real number solution

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SOLUTION: Find all values of t in the interval [0, 2&#960;] satisfying the given equation: 6 sin 2t + 3 tan 2t = 0. And 6 is under a square root! How to get the answer? Thank you!

SOLUTION: Find all values of t in the interval [0, 2π] satisfying the given equation: 6 sin 2t + 3 tan 2t = 0. And 6 is under a square root! How to get the answer? Thank you!