SOLUTION: 2x given tanx= 5/3 and sin x>0

Question 804452: 2x given tanx= 5/3 and sin x>0
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
solve for 2x given tanx= 5/3 and sin x>0
x=acute angle
hypotenuse of reference right triangle=√(5^2+3^2)=√(25+9)=√34
sinx=5/√34
cosx=3/√34
sin2x=2sinxcosx=2*(5/√34)*(3/√34)=30/34=15/17
2x=1.0808

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