SOLUTION: what angles in between pi and 2pi satisfy the equation cos(4x)=0

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Question 803454: what angles in between pi and 2pi satisfy the equation cos(4x)=0
Answer by Edwin McCravy(20064)   (Show Source): You can put this solution on YOUR website!
cos(4x)=0

The angles with cosine 0 are all the odd multiples of 

4x = 

 x = ÷4
 x = 
 x =  

 

Divide all three sides by p

 

Multiply all three sides by 8 to clear of fractions:

 

Subtract 1 from all three sides

 

Divide all three sides by 2

 

Since n is an integer
 
  , 

  n ∈ {4,5,6,7}

Answers:  x =  =  =  
          x =  =  =  
          x =  =  =  
          x =  =  =  

Edwin
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