SOLUTION: Solve the equation on the interval [o,2pi) 1.) cos(2theta - pi/2)= -1 I started off by adding pi/2 to -1 so my new equation is cos2theta=-1/2 Not sure if this is correct but

Question 794776: Solve the equation on the interval [o,2pi)
1.) cos(2theta - pi/2)= -1
I started off by adding pi/2 to -1 so my new equation is cos2theta=-1/2
Not sure if this is correct but I'm stuck there.

2.) tan^2theta=3/2sec theta
I'm completely lost on this probem

Thank you in advance!
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
1.)
There is only one angle in the

interval that has
:

So -->-->-->

2.)
-->
Also
So we can re-write the equation as

Multiplying both sides times we get

Multiplying times 2, we get

Since -->
so we can re-write the equation as
--> -->
Since I'm tired of writing so many times, I will temporarily rename it

Now my equation looks like
The solutions to that equation are and
We can only use --> because .
If and
then or
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