SOLUTION: Find, to the nearest tenth of a degree, all positive angles less than 360° where cos  = -0.5982.
how do you figure this out?
Algebra.Com
Question 788515: Find, to the nearest tenth of a degree, all positive angles less than 360° where cos = -0.5982.
how do you figure this out?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find, to the nearest tenth of a degree, all positive angles less than 360° where cos(x) = -0.5982
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Note: You need a calculator or a trig table to find the angle.
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x = cos^-1(-0.5982) = 107.35 degrees or 360-107.35 = 252.65 degrees
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Cheers,
Stan H.
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