SOLUTION: 20 sin2 x + 21 sin x + 4 = 0 solving trigonometric equations (0,2pi)

SOLUTION: 20 sin2 x + 21 sin x + 4 = 0 solving trigonometric equations (0,2pi)

Algebra.Com

Question 786384: 20 sin2 x + 21 sin x + 4 = 0
solving trigonometric equations (0,2pi)
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!

(5sin(x)+4)((4sin(x)+1)=0
sin(x)=-4/5 OR sinx=-1/4

Now apply (0,2pi)

RELATED QUESTIONS
sin2(x)+sin(x)=0 (answered by Fombitz)

Solve all equations for (0, 2pi) sin(x + (pi/4)) + sin(x - (pi/4)) = 1 (answered by lwsshak3)

Please help me solve this equations: 1. {2 sin x-1=0} 2. graph {f(x)=sin(x-2pi)-1}... (answered by stanbon)

Find all solutions on the interval x element [0, 2pi) for the trigonometric equation... (answered by Fombitz)

Solve the equations of [0, 2pi]: cosx(2sinx-1)=0 and... (answered by lwsshak3)

Find all solutions of each of the equations in the interval (0, 2pi) cos(x- pi/2) +... (answered by lwsshak3)

Use identities to solve trigonometric equation? sin(x) + sin 2(x) = 0 I use... (answered by josgarithmetic)

Find all exact solutions on (0, 2pi) sec(x) sin(x) - 2 sin(x) =... (answered by Boreal,MathLover1)

Find the 4 solutions in the interval [0, 2pi), for the equation, 2cos x sin x + sin x =... (answered by lwsshak3)