You can
put this solution on YOUR website!
From a point A on the ground, the angle of
elevation to the top of a tall building is
24.1 degrees. From a point B, which is 600
ft closer to the building, the angle of
elevation is measured to be 30.2 degrees.
Find the height of the building.
*|C
* * |
* |h
* * |
A_____B_________________|D
600 x
I can't draw slanted lines on here, but you can
on your paper. I've tried to indicate AC and BC
with asterisks " * " above.
Let C be the top of the building and D the bottom of
the building.
There are two right triangles, CAD and CBD.
Let h = CD and x = BD. We are given that AB = 600.
So from right triangle CAD we have:
h
tan(24.1°) = ----------
600 + x
and from right triangle CBD we have:
h
tan(30.2°) = ---
x
To make the algebra easier to write,
let's let:
T = tan(24.1°) and U = tan(30.2°)
Then those two equations are
h
T = ---------
600 + x
and
h
U = --- which means h = Ux
x
Clearing of fractions in those equations
gives these two equations:
h = T(600 + x)
h = Ux
Since both right sides equal h, we set them
equal to each other
Ux = T(600 + x)
Now we solve for x:
Ux = 600T + Tx
Ux - Tx = 600T
x(U - T) = 600T
Divide both sides by (U - T)
600T
x = ---------
U - T
Now we now go back and substitute
for U and T
T = tan(24.1°) and U = tan(30.2°)
and we have:
600·tan(24.1°)
x = ---------------------------
tan(30.2°) - tan(24.1°)
Punch that out on your calculator and you get
x = 1992.638095
Then we can find h from
h = Ux
h = tan(30.2°)(1992.638095)
h = 1159.743065
I'd round that off to 1160 feet.
Edwin