SOLUTION: if a sin^3 theta+b cos^3 theta=sin theta cos theta and a sin theta-b cos theta =0 then prove that a^2+b^2=1
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Question 782104: if a sin^3 theta+b cos^3 theta=sin theta cos theta and a sin theta-b cos theta =0 then prove that a^2+b^2=1
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
a sin^3 theta+b cos^3 theta=sin theta cos theta
a sin theta-b cos theta =0
substitute a in equation a sin^3 theta+b cos^3 theta=sin theta cos theta
Now
substitute b
a= sin(theta).cos(theta)/sin(theta)}}}
so
Therefore
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