SOLUTION: Solve the equation sin (x° - 20°) = cos 42° for x, where 0 < x < 90.

Algebra.Com
Question 774687: Solve the equation sin (x° - 20°) = cos 42° for x, where 0 < x < 90.
Answer by josgarithmetic(39620)   (Show Source): You can put this solution on YOUR website!
cos(42)=sin(90-42)=sin(48)
sin(x-20)=sin(48)
x-20=48
x=48+20
x=68 degrees

RELATED QUESTIONS

Solve the equation sin(x-20)=cos 42 for x, where... (answered by Alan3354)
Which value of x solves the equation cos x° = sin (20° + x°), where 0 < x <... (answered by Alan3354,solver91311)
Solve the equation cos x° = sin 40°, where 0 < x < (answered by ewatrrr)
For what value of x is sin x = cos 19°, where 0°< x < 90°? (answered by Alan3354)
if sin x= 4/5, where 0 (answered by edjones)
For 0 degrees < x < 90 degrees, how many solutions are there for the equation 2 sin x =... (answered by stanbon)
what is the answer to cos x° = sin 40°, where 0 < x <... (answered by tommyt3rd)
solve the equation: sin x(sin x + 1) = 0 4 cos^2 x - 1 =... (answered by ewatrrr)
solve the equation: sin x(sin x + 1) = 0 4 cos^2 x - 1 =... (answered by ewatrrr)