SOLUTION: if A+B=90;SinA=3/4 then secB=?

Question 773994: if A+B=90;SinA=3/4 then secB=?
Answer by Edwin McCravy(20059) (Show Source): You can put this solution on YOUR website!
if A+B=90;SinA=3/4 then secB=?

Since sine = , draw a right triangle
with opposite side the numerator of 3/4, which is 3, and 
a hypotenuse which is the denominator of 3/4, which is 4:

 

A simpler way to do it is this way: 

sin(A) = cos(B) = 3/4, and sec(B) = [reciprocal of cos(B)] = 4/3

{Edwin

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