SOLUTION: solve and state the four exact solutions on the interval [0, 2 pi]: 2 sin (2 x)+ square root 3 = 0

Question 771945: solve and state the four exact solutions on the interval [0, 2 pi]: 2 sin (2 x)+ square root 3 = 0
Answer by oscargut(2103) (Show Source): You can put this solution on YOUR website!
solve and state the four exact solutions on the interval [0, 2 pi]: 2 sin (2 x)+ square root 3 = 0

sin (2 x) = -sqrt(3)/2
2x = 4pi/3 or 2x = 5pi/3
x = 2pi/3 or x = 5pi/6

I can help you with more questions at: mthman@gmail.com
Thanks

RELATED QUESTIONS
Solve on the interval from 0 to pi:2cos^2 x-3 sin... (answered by lwsshak3)

Solve 2 sin^2 x + cos x -2=0 on the interval -pi< x <... (answered by lwsshak3)

How do you solve sin x + square root of 2 = - sin x on the interval -pi/2 < x <... (answered by MathLover1,mananth,ikleyn,math_tutor2020)

Given: cosθ= -3/5 and sinθ > 0. Find the exact value of cos θ/2. solve (answered by lwsshak3)

Please explain hoe to solve the equation for exact solutions over the interval [0, 2pi). (answered by Fombitz)

Find the exact value if 0 < x < pi/2 and 0 < y < pi/2 ; sin(x+y) if sin(x) = 3/5 and... (answered by fractalier)

Find all solutions of each of the equations in the interval [0,2pi). a)... (answered by KMST)

Trigonometry Solve each equation; clearly state the principle root, all solutions in... (answered by lwsshak3)

Solve the equation on the interval [0, 2pi). tan^2 x sin x = tan^2 x B.pi/2 , pi (answered by ikleyn)