SOLUTION: Could you help me solve this? The problem says I need to evaluate it. tan(sin^-1((p)/sqrt(p^2+9))) Thanks!!

Question 769261: Could you help me solve this? The problem says I need to evaluate it.
tan(sin^-1((p)/sqrt(p^2+9)))
Thanks!!
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Evaluate:
tan(sin^-1((p)/sqrt(p^2+9)))
let x=angle of inverse sine
sin x=p/√(p^2+9)
cos x=√(1-sin^2x)
cos x=√(1-(p^2/p^2+9))
cos x=√(p^2+9-p^2)/(p^2+9))
cos x=√(9/(p^2+9))=3/√(p^2+9)
tan x=sin x/cos x=p/3
tan(sin^-1((p)/sqrt(p^2+9)))=p/3
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